Sample Problem : Column Buckling Calculations for a Solid Round Bar

Specify maximum load that can be carried by a round bar with a diameter of 50 mm and length of 2 m. Use design factor of 5 and consider the ends as pinned. The material for the column is selected as ASTM A588 with following properties:

Material properties: Yield Strength: 345 MPa , Modulus of Elasticity: 205 GPa , Density: 7.87 g/cc

Step 1 : Write down input parameters (including material properties) which are defined in the sample example.

 INPUT PROPERTIES SUMMARY Parameter Symbol Value Unit Diameter of column d 50 mm Length of Column L 2 m Design factor nd 5 --- End Condition Pinned-Pinned Yield Strength (A588 Steel) Sy 345 MPa Elastic modulus(A588 Steel) E 205 GPa Density(A204 Steel) ρ 7.87 g/cm3

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Step 5 : Go back to "Compression Member Design"  page and calculate maximum allowable load by using parameters given in step 1 and step 4.

Allowable load (maximum load) that can be carried by the column is calculated as 31.04 kN. This is the answer of the sample example.

Summary

The problem is completely solved with calculators which are summarized as follows.

 Calculator Usage Column Buckling and Compression Member Design To calculate column allowable load for given parameters. In this example, column is classified as long column and Euler equations (Buckling) have been used. Sectional Properties Calculator To calculate sectional properties of standard profiles. In this example, solid circle has been calculated.