# STRESS CONCENTRATION FACTOR FOR ROUND PIN JOINT WITH CLOSELY FITTING PIN IN A FINITE-WIDTH PLATE

Theoretical stress concentration factors (Kt) of round pin joint with closely fitting pin in finite width plate can be calculated by this calculator for tension loads.

There exist some validity conditions for the equations which are used in the calculations. If input parameters don't satisfy validity conditions of equations, a warning message is given by the calculator.

### Round Pin Joint with Closely Fitting Pin in Finite Width Plate:

 INPUT PARAMETERS Parameter Value Plate width [D] mm cm m inch ft Hole diameter [d] Hole center to plate edge distance [L] Plate thickness [h] Tension force [P] N kN lbf

Note: Use dot "." as decimal separator.

 RESULTS LOADING TYPE - TENSION Parameter Value TENSION STRESS Stress concentration factor [Kta] * --- --- Nominal tension stress based on net section [σna ] o --- MPa psi ksi Maximum tension stress [σmax] --- BEARING STRESS Stress concentration factor [Ktb] ** --- --- Nominal bearing stress based on bearing area [σnb ] x --- MPa psi ksi Maximum bearing stress [σmax ] ---

Note 1: * Geometry rises σna by a factor of Kta. (Kta= σmaxna)

Note 2: ** Geometry rises σnb by a factor of Ktb. (Ktb= σmaxnb)

Note 3: o Nominal stress based on net section (σna= P/[(D-d)h])

Note 4: x Nominal stress based on bearing area  (σnb= P/(dh))

### Definitions:

Stress Concentration Factor: Dimensional changes and discontinuities of a member in a loaded structure causes variations of stress and high stresses concentrate near these dimensional changes. This situation of high stresses near dimensional changes and discontinuities of a member (holes, sharp corners, cracks etc.) is called stress concentration. The ratio of peak stress near stress riser to average stress over the member is called stress concentration factor.

Kt: Theoretical stress concentration factor in elastic range = (σmaxnom)

### List of Equations:

 Tension For $$0.15\le \frac { d }{ D } \le 0.75,\quad \frac { L }{ D } \ge 1$$ $${ K }_{ ta }=12.882-52.714\frac { d }{ D } +89.762{ (\frac { d }{ D } ) }^{ 2 }-51.667{ (\frac { d }{ D } ) }^{ 3 }$$ $${ K }_{ tb }=0.2880+8.820\frac { d }{ D } -23.196{ (\frac { d }{ D } ) }^{ 2 }+29.167{ (\frac { d }{ D } ) }^{ 3 }$$ Nominal stress based on net section:  $${ \sigma }_{ na }=P/(D-d)h$$ Nominal stress based on bearing area: $${ \sigma }_{ nb }=P/dh$$ $${ \sigma }_{ max\_ a }={ K }_{ t }{ \sigma }_{ na }$$ $${ \sigma }_{ max\_ b }={ K }_{ t }{ \sigma }_{ nb }$$